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This isn t Clemson coach Dabo Swinney but former Clemson coach Danny Ford Photo by M Bradley dan This isn t Clemson coach Dabo Swinney but former Clemson coach Danny Ford Photo by M Bradley dan
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3 3 l g y a m a c o m 3 3 l g y a m a c o m 3 3 l g y a m a c o m 3 3 l g y a m a c o m
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The reunion we ve long awaited Arthur M Blank and MV7 Photo by M Bradley mv The reunion we ve long awaited Arthur M Blank and MV7 Photo by M Bradley mv
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From Yahoo Image Search: 'M'
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What is the value for m, and how do you solve the equation showing work?
Q. A mass m at the end of a spring vibrates with a frequency of 0.88 Hz. When an additional 680-g mass is added to m, the frequency is 0.60 Hz. What is the value for m, and how do you solve the equation showing work?
Asked by Pat M - Tue Nov 7 18:40:17 2006 - - 3 Answers - 0 Comments
A. After a whole bunch of math my physics book says that w^2 = k/m. Yours probably does too. So, what to do with it? .88^2 = k/m .60^2 = k/(m+680gm) From the 1st one, k = (.88^2)*m. You can solve the 2nd for m from here. Work: W = F*d = -k*d^2
Answered by sojsail - Tue Nov 7 21:10:43 2006
Q. A mass m at the end of a spring vibrates with a frequency of 0.88 Hz. When an additional 680-g mass is added to m, the frequency is 0.60 Hz. What is the value for m, and how do you solve the equation showing work?
Asked by Pat M - Tue Nov 7 18:40:17 2006 - - 3 Answers - 0 Comments
A. After a whole bunch of math my physics book says that w^2 = k/m. Yours probably does too. So, what to do with it? .88^2 = k/m .60^2 = k/(m+680gm) From the 1st one, k = (.88^2)*m. You can solve the 2nd for m from here. Work: W = F*d = -k*d^2
Answered by sojsail - Tue Nov 7 21:10:43 2006
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